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-2x^2-10x=-28
We move all terms to the left:
-2x^2-10x-(-28)=0
We add all the numbers together, and all the variables
-2x^2-10x+28=0
a = -2; b = -10; c = +28;
Δ = b2-4ac
Δ = -102-4·(-2)·28
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-18}{2*-2}=\frac{-8}{-4} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+18}{2*-2}=\frac{28}{-4} =-7 $
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